A mass of 1000kg is released from a height of 10m.with what energy will it strike the floor?(g=10m/s/s)

Do you mean kinetic energy? That would be equal to the potential energy loss, M g H.

The correct value of g is 9.8 m/s^2. They are telling you to use an incorrect value.

To calculate the energy with which the mass will strike the floor, we need to consider both the potential energy it has at the initial height and the kinetic energy it gains during the fall.

1. Calculate the potential energy at the initial height:
Potential energy = mass × gravity × height
Plugging in the values:
Potential energy = 1000 kg × 10 m/s² × 10 m
Potential energy = 100,000 Joules

2. Calculate the kinetic energy at the time of impact:
Kinetic energy = 0.5 × mass × velocity²
Since the mass is dropped and falls downward, the velocity just before impact can be calculated using the formula:
Velocity = √(2 × gravity × height)
Plugging in the values:
Velocity = √(2 × 10 m/s² × 10 m)
Velocity = √(200 m²/s²)
Velocity ≈ 14.14 m/s

Now, calculating the kinetic energy:
Kinetic energy = 0.5 × 1000 kg × (14.14 m/s)²
Kinetic energy ≈ 100,000 Joules

3. Calculate the total energy at impact:
Total energy = Potential energy + Kinetic energy
Total energy = 100,000 Joules + 100,000 Joules
Total energy = 200,000 Joules

Therefore, the mass will strike the floor with an energy of 200,000 Joules.