solve the following equation for the value of theta between 0 degrees and 360 degrees.For 5 + 3cosec^2theta =8
5 + 3 cosec ^ 2 (theta) = 8
3 cosec ^ 2 (theta) = 8 - 5
3 cosec ^ 2 (theta) = 3 Divide both sides by 3
cosec ^ 2 (theta) = 3 / 3
cosec ^ 2 (theta) = 1
cosec (theta) = sqrt ( 1 )
cosec (theta) = + OR - 1
cosec ( theta ) = 1 / sin ( theta )
sin ( theta ) = 1 / cosec ( theta )
sin ( theta ) = + OR - 1
cosec 90 ° = 1
cosec 270 ° = - 1
OR
sin 90 ° = 1
sin 270 ° = - 1
Solutions :
theta = 90 °
and
theta = 270 °