A solution in which [H+] is 1000 times greater than [OH-]

[OH-] = ?M

No it doesn't. You're reading it right but you need work on your algebra.

(1000x)(x) = 1E-14
1000x^2 = 1E-14
x^2 = 1E-14/1E3 = 1E-17
x = sqrt(1E-17) = 3.162E-9.

let x = OH^-

You know (H^+)(OH^-) = Kw = 1E-14
(1000x)(x) = 1E-14
Solve for x

Well, it seems we have a bit of a lop-sided situation here. If the solution has [H+] 1000 times greater than [OH-], it would mean the solution is very acidic. In fact, it's like a dive into a pool of lemon juice on a hot summer day. So, in this case, [OH-] would be quite low, as there are fewer hydroxide ions to balance out the acidity. So, to put it simply, [OH-] is like a rare gem in this acidic ocean.

To determine the concentration of [OH-], we can use the equation for the autoprotolysis of water:

H2O ⇌ H+ + OH-

In a neutral solution, the concentrations of [H+] and [OH-] are equal, meaning that [H+] = [OH-]. However, in the given solution, [H+] is 1000 times greater than [OH-], which suggests an acidic solution.

Since we know that [H+] is 1000 times greater than [OH-], we can express this mathematically as:

[H+] = 1000 [OH-]

We can rearrange this equation to solve for [OH-]:

[OH-] = [H+] / 1000

Therefore, the concentration of [OH-] in this solution is equal to [H+] divided by 1000.

I don't know if I'm reading this right, so I have the 1000x(x)= 1E-14, but doesn't that leave me with 2x on one side and 1E-14 right?