What mass of aluminum is produced by the decompisition of 7.47 kg of Al2O3?
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To determine the mass of aluminum produced by the decomposition of Al2O3, you need to consider the balanced chemical equation for the reaction. The balanced equation for the decomposition of Al2O3 is:
2 Al2O3 → 4 Al + 3 O2
According to the equation, 2 moles of Al2O3 decomposes to form 4 moles of aluminum. From the balanced equation, the molar ratio between Al2O3 and Al is 2:4, which simplifies to 1:2.
To find the mass of aluminum produced, follow these steps:
Step 1: Convert the given mass of Al2O3 to moles.
To convert mass to moles, divide the given mass by the molar mass of Al2O3. The molar mass of Al2O3 can be calculated from the atomic masses of aluminum (Al) and oxygen (O):
Molar mass of Al2O3 : (2 × atomic mass of Al) + (3 × atomic mass of O)
Atomic mass of Al = 26.98 g/mol
Atomic mass of O = 16.00 g/mol
Using these values, calculate the molar mass of Al2O3 and then convert the given mass to moles.
Step 2: Determine the moles of aluminum produced.
Since the molar ratio between Al2O3 and Al is 1:2, the moles of aluminum produced will be twice the moles of Al2O3.
Step 3: Convert moles of aluminum produced to mass.
To convert moles to mass, multiply the moles of aluminum by the molar mass of aluminum. The molar mass of aluminum is:
Molar mass of Al = 26.98 g/mol
Using this value, calculate the mass of aluminum produced.
By following these steps and using the given mass of Al2O3, you can find the mass of aluminum produced by the decomposition of Al2O3.