These are what i used.

0.0375M sodium thiosulphate , 2.5% KI .47.2 ml copper sulphate solution.
the average volume of Na2S2O3 is 19.25 cm, i have already calculated the number of moles of thiosulphate which is 7.218 * 10-4 moles of Na2S2O3 and also the number of moles of I2 that reacted with S2O32 which was calculated to be 7.218*10^-4/2 = 3.609 * 10^-4

I have to do the calculations for :

The number of Cu2+ that reacted with I- to produce the number of moles of I2 above
The number of moles of Cu2+ in the volumetric flask
The concentration of Cu2+ in the stock solution

Any kind of help would be really appreciated!

You started in the middle of the question. I'm just guessing that you have performed an experiment in which you determined %Cu in a sample. The equations are Cu^2+ + KI(xs) ==> CuI(s) + I2 and I suppose you titrated the liberated I2 with thiosulfate like this

2S2O3^2- + I2 ==> 2I^- + S4O6^2-
mols S2O3^2-, what you titrated with is M x L = ?. Then convert this to moles Cu.
? mols S2O3^2- x (1 mol I2/2 mol S2O3^2-) x (2 mol Cu/1 mol I2) =? mol Cu.

To calculate the number of Cu2+ ions that reacted with I- to produce the number of moles of I2, you need to know the stoichiometry of the reaction. If the reaction is balanced, you can determine the ratio of Cu2+ to I2. Once you know this ratio, you can calculate the number of Cu2+ ions.

The balanced chemical equation for the reaction between Cu2+ and I- is:

2Cu2+ + 4I- → 2CuI + I2

From this equation, you can see that 2 moles of Cu2+ react with 4 moles of I- to produce 1 mole of I2. Therefore, the ratio of Cu2+ to I2 is 2:1.

Since you have already calculated the number of moles of I2 to be 3.609 * 10^-4, you can now calculate the number of moles of Cu2+:

Number of moles of Cu2+ = (Number of moles of I2) * (2 moles of Cu2+ / 1 mole of I2)

Number of moles of Cu2+ = 3.609 * 10^-4 * 2 = 7.218 * 10^-4 moles of Cu2+

Next, you need to calculate the number of moles of Cu2+ in the volumetric flask. To do this, you can use the volume of the copper sulfate solution and its concentration.

The moles of Cu2+ can be calculated using the formula:

Number of moles of Cu2+ = (Concentration of Cu2+) * (Volume of solution in liters)

However, you need to convert the volume of the solution from milliliters to liters (47.2 ml to liters):

Volume of solution in liters = 47.2 ml / 1000 = 0.0472 liters

Now, you can calculate the number of moles of Cu2+:

Number of moles of Cu2+ = (Concentration of Cu2+) * (Volume of solution in liters)
7.218 * 10^-4 moles of Cu2+ = (Concentration of Cu2+) * (0.0472 liters)

Solving for the concentration of Cu2+:

Concentration of Cu2+ = (7.218 * 10^-4 moles of Cu2+) / (0.0472 liters)

Concentration of Cu2+ = 0.0153 M

Finally, you have determined the concentration of Cu2+ in the stock solution to be 0.0153 M.