solution to the equation x2 – 9x – 22 = 0?
it factors ....
(x-11)(x+2) = 0
so x = 11 or x = 2
To find the solution to the equation x^2 - 9x - 22 = 0, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 1, b = -9, and c = -22. Plugging these values into the quadratic formula, we get:
x = (-(-9) ± √((-9)^2 - 4(1)(-22))) / (2(1))
Simplifying further:
x = (9 ± √(81 + 88)) / 2
x = (9 ± √169) / 2
x = (9 ± 13) / 2
This gives us two possible solutions:
x = (9 + 13) / 2 = 22 / 2 = 11
x = (9 - 13) / 2 = -4 / 2 = -2
Therefore, the solutions to the equation x^2 - 9x - 22 = 0 are x = 11 and x = -2.
To solve the equation x^2 - 9x - 22 = 0, we can use the quadratic formula. The quadratic formula states that for an equation in the form ax^2 + bx + c = 0, the solution for x can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In our equation, we have a = 1, b = -9, and c = -22. Plugging these values into the formula, we can find the solutions for x.
x = (-(-9) ± √((-9)^2 - 4*1*(-22))) / (2*1)
x = (9 ± √(81 + 88)) / 2
x = (9 ± √169) / 2
x = (9 ± 13) / 2
Therefore, the solutions to the equation x^2 - 9x - 22 = 0 are:
x1 = (9 + 13) / 2 = 22 / 2 = 11
x2 = (9 - 13) / 2 = -4 / 2 = -2
So, the solutions to the equation are x = 11 and x = -2.