1) Complete and balance the following chemical reactins:

2HCI(aq)+Pb(NO3)2(aq)--->
2HI(aq)+K2SO3(s)--->
Pb(NO3)2(aq)+2KCI(aq)--->
Ba(NO3)2(aq)+Na2SO4(aq)--->
K2CO3(aq)+Ba(NO3)2(aq)--->
HCI(aq)+AgNO3(aq)--->

2) How could you separate gold from a mixture of zinc and gold?

3) Using a hydrochloric acid solution, how could you determine whether a white powder was zinc sulfide or silver nitrate? Write balanced equations.

ZnS(s)+2HCI(aq)--->
AgNO3(s)+HCI(aq)--->

THANK YOU SO MUCH!!!!

2) we know that gold is the thing we want.so use a method to have reaction with zinc but not gold.

Hydrochloric acid is a good example.
then use filter and filter paper to filter the gold out

3)AgCl is insoluble in water which is white in colour.its the white precipitate

PbCl2+2HNO3

1) To complete and balance the chemical reactions, we need to follow a few steps:

a) Write the reactants and products in their chemical formulas.

b) Balance the equation by adjusting the coefficients in front of each compound so that the number of atoms on each side is equal.

c) Finally, ensure that the equation is balanced both in terms of atoms and charge.

Let's go through each reaction:

2HCl(aq) + Pb(NO3)2(aq) --> PbCl2(s) + 2HNO3(aq)

2HI(aq) + K2SO3(s) --> 2KHI(aq) + SO2(g)

Pb(NO3)2(aq) + 2KCl(aq) --> PbCl2(s) + 2KNO3(aq)

Ba(NO3)2(aq) + Na2SO4(aq) --> BaSO4(s) + 2NaNO3(aq)

K2CO3(aq) + Ba(NO3)2(aq) --> BaCO3(s) + 2KNO3(aq)

HCl(aq) + AgNO3(aq) --> AgCl(s) + HNO3(aq)

2) To separate gold from a mixture of zinc and gold, we can use a process called selective precipitation. This is based on the fact that gold is insoluble in hydrochloric acid, while zinc can be dissolved.

Steps involved:

a) Add hydrochloric acid to the mixture to dissolve the zinc. The reaction is as follows:
Zn(s) + 2HCl(aq) --> ZnCl2(aq) + H2(g)

b) Filter the resulting solution to separate the insoluble gold particles.

c) Heat the remaining solution to evaporate the water, leaving behind zinc chloride as a solid.

3) When using a hydrochloric acid solution to determine whether a white powder is zinc sulfide or silver nitrate, we can perform separate tests for each compound.

For zinc sulfide (ZnS):
Add hydrochloric acid to the white powder. If it is zinc sulfide, a reaction will occur, producing hydrogen sulfide gas (H2S):
ZnS(s) + 2HCl(aq) --> ZnCl2(aq) + H2S(g)

For silver nitrate (AgNO3):
Add hydrochloric acid to the white powder. If it is silver nitrate, a reaction will occur, producing silver chloride as a solid:
AgNO3(s) + HCl(aq) --> AgCl(s) + HNO3(aq)

By observing the formation of either hydrogen sulfide gas or silver chloride, we can determine which compound is present in the white powder.

No one here will do your home work for you. What do you not understand about these questions?