A box which has a mass of 14kg is sliding along a horizontal surface with a velocity of 18m/s when it encounters a frictionless inclined plane which meets the horizontal at an angle of 28 degrees. The box slides up the incline until it comes to a halt.

How far up the incline will the box slide before it stops? (35.2m)

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  1. its initial KE= final PE

    1/2 m v^2= mgh=mg*distance*sin28
    solve for distance.

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