If the % m/m of a solution of NaCl is 22%, how many grams of NaCl are present in 250g of solution???/

22 g in a 100 soln so

22 x (250/100) in 250 g soln.
Check it.
% m/m = (grams solute/g soln)100 =
(55/250)*100 = 22%