The sum of 3 consecutive intergers is 90. Find the largest interger if x is the smallest interger.
The consecutive integers are 29, 30 and 31.
If x is the smallest integer, the largest must be x + 2.
The sum must be 3x + 3 = 90
x = 29
To find the largest integer, let's start by representing the three consecutive integers.
Let's call the smallest integer "x". The next consecutive integer will be "x + 1", and the one after that will be "x + 2".
The sum of these three consecutive integers is given as 90. So, we can form an equation:
x + (x + 1) + (x + 2) = 90
Now, let's simplify the equation:
3x + 3 = 90
Subtracting 3 from both sides:
3x = 87
Dividing both sides by 3:
x = 29
So, the smallest integer "x" is 29. The largest integer "x + 2" will be:
29 + 2 = 31
Therefore, the largest integer is 31.