solve by the substitution method. 6x+3y=-21 -4x+y=41
there are so many ways of doing this problem! you can solve for x or y.
let's solve for x.
take -4x+y=41
when u solve x= 1/4y-41/4
plug that value of x into the other equation: 6x+3y=-21
it should look like this
6(1/4y-41/4)+3y=-21 and solve for y
after u solve for y
plug it in to whatever equation & solve for x and then u check it.
you can do it vice versa & solve for y first if you want too:)
from the 2nd: y = 41-4x
sub into the 1st:
6x + 3y = -21
6x + 3(41-4x) = -21
6x +123 - 12x = -21
-6x = -144
x = 24
sub into y = 41-4x = 41-4(24) = -55
x = 24
y = -55
just give up your dumb
To solve the system of equations using the substitution method, let's start by solving one equation for one variable and substituting it into the other equation.
Let's solve the second equation, -4x + y = 41, for y:
y = 4x + 41
Now, substitute this value of y into the first equation, 6x + 3y = -21:
6x + 3(4x + 41) = -21
Next, simplify the equation:
6x + 12x + 123 = -21
18x + 123 = -21
To isolate x, subtract 123 from both sides:
18x = -21 - 123
18x = -144
Divide both sides by 18:
x = -144/18
x = -8
Now that we have the value of x, substitute it back into the second equation to solve for y:
y = 4(-8) + 41
y = -32 + 41
y = 9
Therefore, the solution to the system of equations is x = -8 and y = 9.