a quantity of gas is collected over water at 15C. The manometer indicated a pressure of 24.0kPa. what would be the pressure of the dry gas?
24.0 kPa - 1.7 kPa = 22.3 kPa
To find the pressure of the dry gas, you need to apply the vapor pressure of water at 15°C and subtract it from the total pressure indicated by the manometer. The vapor pressure of water at 15°C is 1.17kPa.
Therefore, the pressure of the dry gas can be calculated as follows:
Pressure of dry gas = Total pressure - Vapor pressure of water
Pressure of dry gas = 24.0kPa - 1.17kPa
Pressure of dry gas = 22.83kPa
So, the pressure of the dry gas would be approximately 22.83kPa.
To determine the pressure of the dry gas, we need to account for the pressure exerted by the water vapor in the collected gas. The partial pressure of the water vapor can be calculated using the vapor pressure of water at a given temperature.
Here's how you can solve the problem step by step:
1. Look up the vapor pressure of water at 15°C. The vapor pressure of water at this temperature is approximately 1.76 kPa.
2. Subtract the vapor pressure from the total pressure indicated by the manometer. In this case, subtract 1.76 kPa from 24.0 kPa.
Pressure of dry gas = Total pressure - Vapor pressure of water
= 24.0 kPa - 1.76 kPa
= 22.24 kPa
Therefore, the pressure of the dry gas is approximately 22.24 kPa.