Need help with solving the double equation problem. 3x + 2y = 3
9x - 8y = -2
Indicate your subject in the "School Subject" box, so those with expertise in the area will respond to the question.
Multiply the first equation by 4.
12x +8y = 12
9x - 8y = -2
Add the two equations.
21x = 10
You should be able to proceed from here.
To solve this system of equations, you can use the method of elimination or substitution. Let's use the method of elimination.
First, let's manipulate one of the equations, so that when we add or subtract it to the other equation, one of the variables will cancel out.
Let's multiply the first equation by 3, and the second equation by 1, so that the coefficients of x in both equations match:
Equation 1: 3(3x + 2y) = 3(3) --> 9x + 6y = 9
Equation 2: 1(9x - 8y) = 1(-2) --> 9x - 8y = -2
Now, we can subtract Equation 2 from Equation 1:
(9x + 6y) - (9x - 8y) = 9 - (-2)
9x + 6y - 9x + 8y = 9 + 2
14y = 11
Now, we need to solve for y. Divide both sides of the equation by 14:
14y/14 = 11/14
y = 11/14
Now that we have the value of y, we can substitute it back into one of the original equations to solve for x.
Let's use the first equation:
3x + 2(11/14) = 3
3x + 22/14 = 3
3x = 3 - 22/14
3x = 42/14 - 22/14
3x = 20/14
x = (20/14) / 3
x = 10/21
So, the solution to the system of equations is x = 10/21 and y = 11/14.