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physics

The Ferris Wheel in the figure below is a vertical, circular amusement ride with radius 10 m. Riders sit on seats that swivel to remain horizontal. The Ferris Wheel rotates at a constant rate, going around once in 11 s.
Consider a rider whose mass is 59 kg.

part1
At the bottom of the ride, what is the y
component of the rate of change of the rider’s momentum? (In all of your answers, define the +y direction to be upward and the +x direction to be toward the right.)
part2
At the bottom of the ride, what is the magnitude of the gravitational force on the rider?
part 3
At the bottom of the ride, what is the y
component of the force exerted by the seat on the rider?

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mo

  1. A circular-motion addict of mass 80 kg rides a Ferris wheel around in a vertical circle of radius 10 m at a constant speed of 6.1 m/s. (a) What is the period of the motion? What is the magnitude of the normal force on the addict from the seat when both go through (b) the highest point of the circular path and (c) the lowest point?



    c=2ðr
    c= 2(ð) (10 m)
    c = 62.83185

    period =2ðr
    t

    p= 2(ð) (10 m)
    6.1 m/s

    p= 62.83185
    6.1/s

    p= 10.3003 s

    b) The highest point of the circular path

    F Centripetal = m(g)-m(v2)
    r

    = __80(9.8)-(80)( 6.1)2___
    10m

    = 219.28 N

    c) The lowest point of the circular path

    F Centripetal = m(g)-m(v2)
    r

    = __80(9.8)+(80)( 6.1)2___
    10m

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    Anonymous

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