Write the formula for each of the following compounds, being sure to use brackets to indicate the coordination sphere.

A) bis(bipyridyl)cadmium(II) chloride

B) potassium tetrabromo(ortho-phenanthroline)- cobaltate(III)

Cd(bipy)2Cl2

A) To write the formula for bis(bipyridyl)cadmium(II) chloride, we need to break down the name:

- "bis" means there are two bipyridyl ligands
- "cadmium(II)" indicates the central metal ion is cadmium in its +2 oxidation state
- "chloride" refers to the anionic chloride ligand

So, the formula can be written as [Cd(bipyridyl)2]Cl2.

B) To write the formula for potassium tetrabromo(ortho-phenanthroline)-cobaltate(III), we need to interpret the name:

- "potassium" is the cationic potassium ion
- "tetrabromo" indicates there are four bromide ligands present
- "ortho-phenanthroline" refers to the ligand ortho-phenanthroline, which chelates to the central metal ion cobalt
- "cobaltate(III)" indicates the central metal ion is cobalt in its +3 oxidation state

So, the formula can be written as [Co(ortho-phenanthroline)Br4]K.

To write the formula for each compound, we need to determine the formula of the ligands (the molecules or ions that coordinate to the central metal atom) and the charge of the central metal atom or ion.

A) bis(bipyridyl)cadmium(II) chloride.

In this compound, the ligand is bipyridyl and the central metal atom is cadmium in its +2 oxidation state. The name "bis" indicates that there are two bipyridyl ligands coordinated to the cadmium atom. The compound also contains chloride ions.

The chemical formula for bipyridyl is C10H8N2. Since there are two bipyridyl ligands, the formula of the ligands becomes [C10H8N2]2.

The formula of cadmium(II) ion is Cd2+.

To write the formula, we can place the ligand formula in brackets and indicate the number of ligands using prefixes. Then, we write the central metal atom's symbol followed by its charge outside the brackets, and finally the anion (if present).

So, the formula for bis(bipyridyl)cadmium(II) chloride is [Cd([C10H8N2]2)2]Cl2.

B) potassium tetrabromo(ortho-phenanthroline)- cobaltate(III).

In this compound, the ligand is ortho-phenanthroline and the central metal atom is cobalt in its +3 oxidation state. The ligand is bromine in its -1 oxidation state. The compound also contains a potassium ion.

The chemical formula for ortho-phenanthroline is C12H8N2. Since there are four ortho-phenanthroline ligands, the formula of the ligands becomes [C12H8N2]4.

The formula for bromine is Br^-.

The formula for potassium is K^+.

To write the formula, we can place the ligand formula in brackets and indicate the number of ligands using prefixes. Then, we write the central metal atom's symbol followed by its charge outside the brackets. Next, we add the ligand anion and cation symbols outside the brackets.

So, the formula for potassium tetrabromo(ortho-phenanthroline)-cobaltate(III) is [Co([C12H8N2]4)Br4]K.