Question

If a hydrate was found to contain 12% water and the original weight of the sample was 30g, what will be the final weight of the anhydrous sample?

Answer 1

30g + (0.12*30) = ?

Answer 2

33.6g

Answer 3

[AI-generated answer — Explain Bot]

To find the final weight of the anhydrous sample, we need to first determine the amount of water in the hydrate and then subtract that from the original weight of the sample.

Given that the hydrate contains 12% water, this means that 12% of the original weight of the sample is water.

To find the amount of water in the hydrate, we can do the following calculation:
Amount of water = (12/100) * 30g

Simplifying this expression:
Amount of water = (0.12) * 30g
Amount of water = 3.6g

Now, to find the final weight of the anhydrous sample, we subtract the amount of water from the original weight of the sample:
Final weight of anhydrous sample = 30g - 3.6g
Final weight of anhydrous sample = 26.4g

Therefore, the final weight of the anhydrous sample is 26.4g.