Math

I need help solving this logarithmic function: x = log3(4^3).

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  1. log3 (4^3) = 3 log3 (4)
    the real problem is to find log base 3 of 4

    Let x = log3(4)
    then
    3^x = 4
    we can take base ten logs of both sides with our calculators
    x log 10 (3) = log 10 (4)
    x = log 10 (4) / log 10 (3)
    x = .60206 / .47712
    x = log3 (4) = 1.262
    we want 3 x = 3.786

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    posted by Damon

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