Replace each letter with a number to make the problem correct. Identicle letters are placed with identicle numbers. PARTS x 4 = STRAP
WIth different letters but the same result:
ABCDE x 4 = EDCBA
Lets take it one number at a time.
1--A must be either 1 or 2 or the answer would be a 7 digit number.
2--If A = 1, the 4 x E has to end with 1 which cannot be, so A = 2.
3--If A = 2, then E can only be 3 or 8 for the product to end in 2.
4--But since 4 x E = E, E must be 8 to satisfy both conditions.
5--4 x B can have no carryover to 4 x 2 so B must be 1 as A is already 2.
6--4 x D + the 3 carryover must equal 11, 21, or 31 since B = 1.
7--So D can only be 2 or 7 but since A = 2, D must be 7.
8--4 x 1 must have a carryover of 3 to become 7 so C must be 7, 8 or 9.
9--Since D = 7 and E = 8, C must be 9.
10--Therefore, the numbers are 21978 x 4 = 87912.
PARTS = 21978
I got it the hard way, by trial and error, after realizing that P had to be 2 and S had to be 8.
This kind of problem is not algebra; it is a riddle. There is no guarantee that there would be only one solution. It just turns out that way.
PARTS x 4 = 87912
In looking at the numbers that I tried, without using the same number twice, only those with P = 2, A = 1, S = 8 and T = 7 would start out with 8 and end with 12 when multiplied by 4. That left only a few R numbers to try.
5--4 x B can have no carryover to 4 x 2 so B must be 1 as A is already 2.
why can't B be 0 at step 5? At this point, B can be 0,1,2, and you can eliminate 2 per your reason, but you can't eliminate 0 yet--which makes the rest of your steps invalid.
4A72
B85C
92D6
Answer
E 7775
thanks you are a big help
I NOT HAS MINE
IT IS HAS MINJES
To solve this problem, you need to replace each letter with a number in a way that makes the equation correct. To do this, you can follow these steps:
1. Start by assigning a unique number to each letter. For example, you can assign P = 1, A = 2, R = 3, T = 4, and S = 5.
2. Replace each letter in the equation with its corresponding number. Therefore, the equation becomes: 14325 x 4 = 53231.
3. Solve the equation by multiplying 14325 by 4. The result is 57300.
4. Now, check if the result matches the word obtained by replacing the letters in "STRAP" with the corresponding numbers. So, "STRAP" becomes 53231.
5. Since the result, 57300, matches the word "STRAP" when the letters are replaced by their corresponding numbers, our original answer is correct.
Therefore, the solution is P = 1, A = 2, R = 3, T = 4, and S = 5, which means the numbers that satisfy the equation "PARTS x 4 = STRAP" are P = 1, A = 2, R = 3, T = 4, and S = 5.