balance H3PO4 plus KOH produce K2HPO4 plus H20 and give the name of it
To balance the chemical equation H3PO4 + KOH -> K2HPO4 + H2O, you need to make sure that both sides of the equation have an equal number of atoms of each element. Here's how you can balance this equation:
1. Count the number of atoms for each element on both sides of the equation:
H3PO4: 1 H atom, 3 O atoms, 1 P atom
KOH: 1 K atom, 1 O atom, 1 H atom
K2HPO4: 2 K atoms, 1 H atom, 1 P atom, 4 O atoms
H2O: 2 H atoms, 1 O atom
2. Start by balancing the atoms that appear in the fewest number. In this case, it's the K atoms.
Add a coefficient of 2 before KOH and K2HPO4 to balance the number of K atoms.
The balanced equation now looks like this:
2 H3PO4 + 2 KOH -> K2HPO4 + H2O
3. Next, balance the H atoms by adding a coefficient of 6 in front of H2O:
2 H3PO4 + 2 KOH -> K2HPO4 + 6 H2O
4. Finally, balance the O atoms. The O atoms are already balanced on the left side, so you need to balance the number of O atoms on the right side.
Add a coefficient of 4 in front of KOH, and a coefficient of 3 in front of H3PO4:
3 H3PO4 + 4 KOH -> K2HPO4 + 6 H2O
The balanced equation is:
3 H3PO4 + 4 KOH -> K2HPO4 + 6 H2O
The name of the balanced equation is the reaction between phosphoric acid (H3PO4) and potassium hydroxide (KOH) to produce potassium hydrogen phosphate (K2HPO4) and water (H2O).