Find the ratio of surface area to volume for a cube with a volume of 64 in^3.
I have now done quite a few of these type of questions for you.
Show me that you can do this easy one.
v = s^3
64 = s^3
s = 4 in
SA = 6s^2
= 6 x 4^2
= 1024 in^2
Now I know v = 64 in^3 & SA = 1024 in^3
The ratio is 1024/64 = 16:1
is it right????
6 x 4^2
= 6x16
= 96 , not 1024
so ratio is 96/64 = 3/2
thanks
To find the ratio of surface area to volume for a cube, we first need to calculate the surface area and volume of the cube.
The surface area of a cube is given by the equation: S = 6s^2
where S represents the surface area and s represents the length of one side of the cube.
The volume of a cube is given by the equation: V = s^3
where V represents the volume and s represents the length of one side of the cube.
We are given that the volume of the cube is 64 in^3. So we can set up the equation:
64 = s^3
To solve for s, we can take the cube root of both sides:
∛64 = ∛(s^3)
4 = s
Now that we know the length of one side of the cube (s = 4 in), we can calculate the surface area:
S = 6s^2
S = 6(4^2)
S = 6(16)
S = 96 in^2
Finally, we can find the ratio of surface area to volume:
Ratio = Surface Area / Volume
Ratio = 96 in^2 / 64 in^3
Ratio = 1.5 in^(-1)
Therefore, the ratio of surface area to volume for the given cube is 1.5 in^(-1).