line xy is translated 3 units to the left. if a point on line xy is located at (2,11), where would the equivalent point be on line X and Y prime?

a)(2,14)
b)(2,8)
c)(-1,11)
d)(5,11)

I think the answer is c. What I did is move the point 3 units to the left and and subtracted 3 from 2 and it gave me (-1,11). Am I right?

Yes, you are correct. To determine the location of the equivalent point on line X and Y prime, you need to apply the translation of moving 3 units to the left.

The original point on line XY is located at (2,11). When you move a point to the left, you subtract the given number of units from its x-coordinate. In this case, you need to subtract 3 units from the original x-coordinate of 2.

So, 2 - 3 = -1. Therefore, the x-coordinate of the equivalent point on line X and Y prime would be -1.

The y-coordinate of the point remains the same, so it remains 11.

Hence, the correct answer is (c) (-1,11), as you correctly calculated.