One-third of a number, decreased by thirty-six, is at most twenty-two. Find the number.
Please help me
x= unknown number
1/3x-36=22 is the equation
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1/3x=22+36
1/3x=58
You must do the inverse operation on both sides of the equation.
(1/3x-36+36=22+36)--> (1/3x=58)
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x=174
Again do the inverse operation on both sides. (3/1 x 1/3x=3/1 x 58)-->(x=174)
To find the number, we'll first set up the equation based on the given information.
Let's assume the number is represented by 'x.'
According to the problem, one-third of 'x,' decreased by thirty-six, is at most twenty-two. Mathematically, this can be written as:
(1/3)x - 36 ≤ 22
Now, we can solve the equation step by step to find the value of 'x.'
Step 1: Add 36 to both sides of the inequality to isolate the term with 'x':
(1/3)x ≤ 22 + 36
Simplifying further:
(1/3)x ≤ 58
Step 2: Multiply both sides of the inequality by 3 to eliminate the fraction:
3 * (1/3)x ≤ 3 * 58
Simplifying:
x ≤ 174
Therefore, the solution to the equation is x ≤ 174.
This means that any number 'x' that satisfies the inequality will be less than or equal to 174. So, the number we are looking for can be any number less than or equal to 174.