find the mass of sodium chloride formed when 6.9g of sodium burns in a gas jar filled with chlorine gas.
To find the mass of sodium chloride formed, we need to calculate the molar ratios between sodium and chlorine in the reaction. Here's how you can do it step by step:
Step 1: Write the balanced chemical equation for the reaction.
2Na + Cl2 → 2NaCl
Step 2: Determine the molar mass of sodium chloride (NaCl).
Molar Mass of Na = 22.99 g/mol
Molar Mass of Cl = 35.45 g/mol
Molar Mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol
Step 3: Calculate the number of moles of sodium (Na) using the given mass.
Moles of Na = Mass of Na / Molar Mass of Na
= 6.9 g / 22.99 g/mol
= 0.30 mol
Step 4: Determine the mole ratio between sodium (Na) and sodium chloride (NaCl) from the balanced chemical equation.
From the balanced equation: 2 moles of Na react to form 2 moles of NaCl
Therefore, the mole ratio between Na and NaCl is 2:2, which simplifies to 1:1.
Step 5: Calculate the number of moles of sodium chloride (NaCl) formed using the mole ratio.
Moles of NaCl = Moles of Na
Step 6: Calculate the mass of sodium chloride (NaCl) formed using the molar mass of NaCl.
Mass of NaCl = Moles of NaCl × Molar Mass of NaCl
= 0.30 mol × 58.44 g/mol
= 17.53 g
Therefore, the mass of sodium chloride formed when 6.9 g of sodium burns in a gas jar filled with chlorine gas is 17.53 g.