Physics

A train moving at a constant speed on a surface inclined upward at 10.0° with the horizontal travels a distance of 400 meters in 5 seconds. Calculate the vertical velocity component of the train during this time period.

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asked by Lauren01
  1. Goes up distance 400 sin 10 = 69.5 m

    69.5 m/ 5 s = 13.9 m/s up

    posted by Damon
  2. A train moving at a constant speed on a surface inclined upward at 10.0° with the horizontal travels a distance of 400 meters in 5 seconds. Calculate the vertical velocity component of the train during this time period

    posted by Anonymous

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