# Physics

A train moving at a constant speed on a surface inclined upward at 10.0° with the horizontal travels a distance of 400 meters in 5 seconds. Calculate the vertical velocity component of the train during this time period.

1. 0
2. 6
asked by Lauren01
1. Goes up distance 400 sin 10 = 69.5 m

69.5 m/ 5 s = 13.9 m/s up

posted by Damon
2. A train moving at a constant speed on a surface inclined upward at 10.0° with the horizontal travels a distance of 400 meters in 5 seconds. Calculate the vertical velocity component of the train during this time period

posted by Anonymous

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