If 150.0 grams of iron at 95.0 degrees Celcius, is placed in an insulated container containing 500.0 grams of water at 25.0 degrees Celcius, and both are allowed to come to the same temperature, what will that temperature be? The specific heat of water is 4.18 J/g degrees Celcius and the specific heat of iron is 0.444 J/g degrees Celcius.
heat lost by Fe + heat gained by H2O = 0
[mass Fe x specific heat Fe x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tnitial)] = 0
Solve for Tfinal.posted by DrBob222
21.6posted by Tom
posted by cameren