one angle of triangle measures 110 degrees the other two angles are in a ratio of 5:9 what are the measures of those tow agnels
this did not help at all I hate it so much it made me fail my test!!!
To find the measures of the other two angles, we can let the two angles be 5x and 9x.
Since the sum of the angles in a triangle is 180 degrees, we can set up an equation:
110 + 5x + 9x = 180
Combining like terms, we have:
14x = 70
Dividing both sides by 14, we get:
x = 5
Now we can substitute x back into the expressions for the two angles:
5x = 5(5) = 25 degrees
9x = 9(5) = 45 degrees
Therefore, the other two angles measure 25 degrees and 45 degrees.
To find the measures of the other two angles, let's assign variables to them. Let's call one angle "5x" and the other angle "9x" because they are in a ratio of 5:9.
Given that one angle measures 110 degrees, we can set up an equation:
110 + 5x + 9x = 180
Simplifying the equation, we have:
110 + 14x = 180
Now, subtract 110 from both sides of the equation:
14x = 180 - 110
14x = 70
Divide both sides of the equation by 14 to solve for x:
x = 70 / 14
x = 5
Now, substitute the value of x back into the original equation:
5x = 5 * 5 = 25 (measure of the first angle)
9x = 9 * 5 = 45 (measure of the second angle)
Therefore, the measures of the other two angles are 25 degrees and 45 degrees respectively.
A , B and C = The angles of a triangle
A = 110 °
The angles of a triangle always sum to 180 °
A + B + C = 180 °
110 ° + B + C = 180 °
B + C = 180 ° - 110 °
B + C = 70 °
B / C = 5 / 9 Multiply both sides by C
B = 5 C / 9
B + C = 70 °
5 C / 9 + C = 70 °
5 C / 9 + 9 C / 9 = 70 °
14 C / 9 = 70 ° Multiply both sides by 9
14 C = 70 ° * 9
14 C = 630 ° Divide both sides by 14
C = 630 ° / 14
C = 45 °
B = 5 C / 9
B = 5 * 45 ° / 9
B = 225 ° / 9
B = 25 °