x=3y+2
Write the equation in slope–intercept form.
(b) Give the slope and y-intercept of the line
or
3y+2 = x
3y = x - 2
y = (1/3)x - 2/3
d=9in
To write the equation in slope-intercept form, we need to express it as y = mx + b, where m represents the slope and b represents the y-intercept.
Given equation: x = 3y + 2
First, let's isolate y by moving the term with y to the other side:
2 = 3y - x
Next, let's divide both sides of the equation by 3 to solve for y:
(2/3) = (3y - x)/3
Simplifying the right side gives us:
(2/3) = y - (x/3)
Now, let's rewrite the y-term first and the constant term second:
y = (-x/3) + (2/3)
Finally, we have the equation in slope-intercept form:
y = (-1/3)x + 2/3
So, the slope of the line is -1/3, and the y-intercept is 2/3.