The boiling point of an aqueous solution is 102.35 °C. What is the freezing point? Constants can be found here.
delta T = Kb*m
Solve for molality.
delta T = Kf*m
Solve for delta T.
Subtract delta T from zero to find new f.p.
I keep getting 372. but this can't be right... what am I doing wrong?
To find the freezing point of an aqueous solution, we need to use the equation for freezing point depression. This equation is given by:
ΔTf = i * Kf * m
Where:
ΔTf is the change in freezing point (in °C)
i is the van't Hoff factor (the number of particles the solute dissociates into)
Kf is the cryoscopic constant (a constant that depends on the solvent)
m is the molality of the solution (moles of solute per kilograms of solvent)
Since the question doesn't provide information about the solute or its molality, we can't directly calculate the freezing point. We need the concentration of the solute in order to determine the molality of the solution.
Once we have the molality, we can use the equation to find ΔTf. Subtracting this value from the normal freezing point of water (0 °C) will give us the freezing point of the aqueous solution.
Please provide additional information about the solute and its concentration, so I can help you calculate the freezing point of the solution.
Kb=1.86
Kf=.52