1.The cost, in millions of dollars, to remove x % of pollution in a lake modeled by C=6000/200-2x.
a.What is the cost to remove 75% of the pollutant?
Answer: $30.2 million dollars
b.What is the cost to remove 90 % of the pollutant?
Answer: $30.27 million dollars
c.What is the cost to remove 99% of the pollutant?
Answer: $30.3 million dollars
d.For what value is this equation undefined?
2.Biologists want to set up a station to test alligators in the lake for West Nile Virus. Suppose that the costs for such a station are $2,500 for setup costs and $3.00 to administer each test.
a.Write an expression that gives the total cost to test x animals.
3500 + 3x
b.You can find the average cost per animal by dividing total costs by number of animals. Write the expression that gives the average cost per animal.
3500+3x/x
c.Find the average cost per animal for 10 animals. 100 animals. 1,000 animals.
For 10: $253
For 100: $28
For 1000: $5.50
d.As the number of animals tested increases, what happens to the average cost to test the animals? Would the average cost ever fall below $3.00? If so, identify a value that supports your answer. If not, explain how you know.
Answer: As the number tested increases, the average cost to test the animals decreases. The average cost would not fall below $3.00. An explanation is below
e.How many animals should be tested for the average cost to be $5.00 per animal?
Answer: 1250 animals need to be tested
1a. C = 6000/(200-2x), with x in %
For x = 90%, that is 6000/20 = 300 (million $)
You must be doing something wrong.
2a. No
C = 2500 + 2x
You say the fixed cost is $2500. Where did the $3500 figure come from?
See how you do on the rest of the questions after making those corrections
a.What is the cost to remove 75% of the pollutant?
Answer: $120 million dollars
b.What is the cost to remove 90 % of the pollutant?
Answer: $300 million dollars
c.What is the cost to remove 99% of the pollutant?
Answer: $3 billion dollars
d.For what value is this equation undefined?
I don't understand this
2.Biologists want to set up a station to test alligators in the lake for West Nile Virus. Suppose that the costs for such a station are $2,500 for setup costs and $3.00 to administer each test.
a.Write an expression that gives the total cost to test x animals.
I meant to write 2500 and I got the 3 from above. The $3.00.
2500 + 3x
b.You can find the average cost per animal by dividing total costs by number of animals. Write the expression that gives the average cost per animal.
2500+3x/x
Eat it.
Worse than just homework from a college level course, it is two identical questions from one of the exams;I certainly hope you just used the formula and figured it out for yourself.
However, your question did help me to realize that I was converting 75% to .75 which was not giving me the right answer - apparently it needs to be left as 75. Once I realized this, I did the work - including the first problem - on my own and checked it. If you did the same, ok.
But when you ask for help with an exam question and do not substitute different values than what is on the test, I believe it qualifies as cheating. You might want to keep an eye on that because if you get caught they might drop you from the school.
I think it is nothing wrong for asking for homework help. I am sure you have ask for help in school before so stop trying to be hateful and how do you know if he or she is asking a test question. If you do not want to help then go away and as for the person who was asking for help I was trying to figure out if I should convert 75 into a decimal to, so I understand as well now. Good luck with homework for the person who is asking for help.
This is an exact copy of Appendix D from week 4 of MAT/117 at University of Phoenix. (Not an exam. But an entire homework assignment.) Every single assignment can be found posted to many different sites by many different students. I sometimes look them up to check a few of my answers. ^__^
You know what I find funny? The fact that the people claiming those asking for help are cheaters. Question I have to ask is what are you doing here?
Next, as long as your using this site for actual help and not copying everything then I think its fine.Need help setting up an equation? Just fine. Looking for all the right answers? Your cheating.
Hey, If people want to post the answer and you smart enough to get it only you have to pay the price, other than that who cares if one is cheating.
To find the answers to these questions, we need to substitute the given percentages or values into the given equations and simplify them.
a. To find the cost to remove 75% of the pollutant, we substitute x = 75 in the equation C = 6000 / (200 - 2x):
C = 6000 / (200 - 2(75))
C = 6000 / (200 - 150)
C = 6000 / 50
C = 120
So the cost to remove 75% of the pollutant is $120 million dollars.
b. To find the cost to remove 90% of the pollutant, we substitute x = 90 in the equation C = 6000 / (200 - 2x):
C = 6000 / (200 - 2(90))
C = 6000 / (200 - 180)
C = 6000 / 20
C = 300
So the cost to remove 90% of the pollutant is $300 million dollars.
c. To find the cost to remove 99% of the pollutant, we substitute x = 99 in the equation C = 6000 / (200 - 2x):
C = 6000 / (200 - 2(99))
C = 6000 / (200 - 198)
C = 6000 / 2
C = 3000
So the cost to remove 99% of the pollutant is $3000 million dollars (or $3 billion).
d. To find the value for which the equation is undefined, we need to find the value of x that makes the denominator (200 - 2x) equal to zero.
200 - 2x = 0
2x = 200
x = 100
So the equation is undefined for x = 100.
Now let's move on to the second question:
a. The expression that gives the total cost to test x animals is 3500 + 3x. The setup cost of $2500 is added to the cost of $3 per animal.
b. The expression that gives the average cost per animal is (3500 + 3x) / x.
c. To find the average cost per animal for different values of x, we substitute the given values into the expression:
For 10 animals:
Average cost = (3500 + 3 * 10) / 10 = 3530 / 10 = $353
For 100 animals:
Average cost = (3500 + 3 * 100) / 100 = 3800 / 100 = $38
For 1000 animals:
Average cost = (3500 + 3 * 1000) / 1000 = 6500 / 1000 = $6.50
d. As the number of animals tested increases, the average cost per animal decreases because the fixed setup cost is divided among more animals. The average cost will never fall below $3 per animal because each test costs $3. This means that even if there are no animals to test, there is still a cost of $2500 for the setup.
e. To find the number of animals needed for the average cost to be $5.00 per animal, we set up the equation:
(3500 + 3x) / x = 5
Simplifying the equation, we get:
3500 + 3x = 5x
2x = 3500
x = 1750
So 1750 animals need to be tested for the average cost to be $5.00 per animal.