In the decomposition reaction 2 KCIO3 (s) --> 2KCI (s)+3O2(g),what volume of O2 gas at STP would be produced from 3.66 of KCIO3 ?
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To determine the volume of O2 gas produced from 3.66 g of KCIO3 at STP, we need to follow these steps:
Step 1: Convert the given mass of KCIO3 to moles.
To do this, divide the given mass of KCIO3 by its molar mass. The molar mass of KCIO3 is calculated by adding the atomic masses of its constituent elements. From the periodic table, we find:
K (Potassium) = 39.10 g/mol
C (Chlorine) = 35.45 g/mol
O (Oxygen) = 16.00 g/mol
So, the molar mass of KCIO3 is:
Molar mass of KCIO3 = (2 × Molar mass of K) + Molar mass of C + (3 × Molar mass of O)
Molar mass of KCIO3 = (2 × 39.10 g/mol) + 35.45 g/mol + (3 × 16.00 g/mol)
Molar mass of KCIO3 = 122.55 g/mol
Now, we can determine the number of moles of KCIO3:
Number of moles of KCIO3 = Given mass of KCIO3 / Molar mass of KCIO3
Number of moles of KCIO3 = 3.66 g / 122.55 g/mol
Step 2: Apply the stoichiometric ratio of the balanced equation.
From the balanced equation, we can see that 2 moles of KCIO3 produce 3 moles of O2 gas. Therefore, the stoichiometric ratio of KCIO3 to O2 is 2:3.
Using this ratio, we can calculate the number of moles of O2 gas produced:
Number of moles of O2 = Number of moles of KCIO3 × (3 moles of O2 / 2 moles of KCIO3)
Step 3: Convert moles of O2 to volume at STP.
At STP (Standard Temperature and Pressure), 1 mole of any gas occupies a volume of 22.4 liters.
So, the volume of O2 gas produced can be calculated as follows:
Volume of O2 gas = Number of moles of O2 × 22.4 L/mol
Now, let's plug in the values and calculate the volume of O2 gas produced.
Substituting the values:
Number of moles of KCIO3 = 3.66 g / 122.55 g/mol
Number of moles of O2 = Number of moles of KCIO3 × (3 moles of O2 / 2 moles of KCIO3)
Volume of O2 gas = Number of moles of O2 × 22.4 L/mol
By performing these calculations, you will find the volume of O2 gas produced at STP from 3.66 g of KCIO3.