Could someone look over this paper before I turn it in? Thanks
Hint: Pay attention to the units of measure. You may have to convert from feet to miles several times in this assignment. You can use 1 mile = 5,280 feet for your conversions.
1. Many people know that the weight of an object varies on different planets, but did you know that the weight of an object on Earth also varies according to the elevation of the object? In particular, the weight of an object follows this equation: , where C is a constant, and r is the distance that the object is from the center of Earth.
a. Solve the equation w=cr^-2 for r.
w = Cr^-2,
w/C = r^-2
w/C = 1/r^2
(w/C)^2 = 1/r
r = 1/(w/C)^2
b. Suppose that an object is 100 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is 3,963 miles from the center of the Earth.)
100 = C(3,963)^-2
100 = C(62.950)
C = 100 / 62.95
C = 1.58
c. Use the value of C you found in the previous question to determine how much the object would weigh in
i. Death Valley (282 feet below sea level).
5280 feet = 1 mile
282 feet = 282 / 5280 = 0.053 miles
Therefore r = 3,963 - 0.053 = 3962.94 miles
Since C = 1.58, therefore
w = 1.58(3962.94)^-2
w = 1.58(62.95)
w = 99.46 pounds
ii. the top of Mount McKinley (20,320 feet above sea level).
5280 feet = 1 mile
20,320 feet = 20,320 / 5280 = 3.84 miles
Therefore r = 3963 + 3.84 = 3966.84 miles
Since C = 1.58, therefore
w = 1.58(3966.84)^-2
w = 1.58(62.98)
w = 99.50 pounds
2. The equation gives the distance, D, in miles that a person can see to the horizon from a height, h, in feet.
a. Solve this equation for h.
H=(D/1.2)^2
H=D^2/1.44
b. Long’s Peak in Rocky Mountain National Park, is 14,255 feet in elevation. How far can you see to the horizon from the top of Long’s Peak? Can you see Cheyenne, Wyoming (about 89 miles away)? Explain your answer.
14,255=D^2/1.44
D^2=14,525*1.44
D^2=20,916
D=144.62
Yes Cheyenne, Wyoming can be seen because 89 miles is less than the 144.6
1a.
w=cr^-2
w/c = r^-2
c/w = r^2
√(c/w) = r
1b.
100 = C(3,963)^-2
100 = C/39632
C = 100 * 15705369
C = 1570536900 = 1.57*10^9
1ci.
w = 1570536900/3962.942
w = 100.0030281
it is heavier because it is closer to the center of the earth
1cii.
w = 1570536900/3966.842
w = 99.806489
2a. OK
2b. OK
To look over the paper, you can follow these steps:
1. Start by reading the paper thoroughly to understand the content and identify any errors or areas that need improvement.
2. Pay close attention to the units of measure as mentioned in the hint. If there are conversions involved, make sure to apply them correctly.
3. Check the calculations for accuracy. Verify that the equations have been solved correctly and all steps have been shown.
4. Evaluate whether the answers provided align with the given information and calculations. Double-check that the correct formula has been used for each question.
5. If you notice any mistakes or areas of confusion, provide clear feedback or suggestions for improvement. Consider offering explanations and examples to support your feedback.
Remember that reviewing and proofreading a paper thoroughly is essential to ensure accuracy and clarity in the final submission.