3 kids can buy a hot lunch salad bar or bring from home. On a slip of paper they each write a number 1,2, Or 3. They add the sum to find the total. If te sum is 3,4, or 5 they buy a hot lunch if it is 6 or 7 they buy a salad bar if the sum is 8 or 9 they bring a lunch from home. If they play they game every day what lunch do you think that they will buy the mOst.?
* I was thinking u would use a combination is this correct?
Yes, you are correct. To determine which lunch option the three kids will buy the most often, we need to consider all the possible combinations of numbers they can write on the slips of paper.
Let's break down the possible combinations and calculate the sum for each:
- 1, 1, 1: Sum = 1 + 1 + 1 = 3
- 1, 1, 2: Sum = 1 + 1 + 2 = 4
- 1, 1, 3: Sum = 1 + 1 + 3 = 5
- 1, 2, 1: Sum = 1 + 2 + 1 = 4
- 1, 2, 2: Sum = 1 + 2 + 2 = 5
- 1, 2, 3: Sum = 1 + 2 + 3 = 6
- 1, 3, 1: Sum = 1 + 3 + 1 = 5
- 1, 3, 2: Sum = 1 + 3 + 2 = 6
- 1, 3, 3: Sum = 1 + 3 + 3 = 7
And so on...
By considering all the possible combinations, we can calculate the frequency of each sum:
- Sum 3 appears once
- Sum 4 appears twice
- Sum 5 appears three times
- Sum 6 appears three times
- Sum 7 appears three times
- Sum 8 appears twice
- Sum 9 appears once
Now let's analyze the results based on the lunch options associated with each sum:
- Sum 3, 4, or 5: Buy a hot lunch
- Sum 6 or 7: Buy a salad bar
- Sum 8 or 9: Bring a lunch from home
From the frequency count, we see that there are a total of 6 combinations (out of 27) that would result in the kids buying a hot lunch (sum 3, 4, or 5). There are 6 combinations that would result in buying a salad bar (sum 6 or 7), and 2 combinations that would result in bringing a lunch from home (sum 8 or 9).
Therefore, based on the given conditions, it is most likely that the three kids will buy a salad bar the most often, as they have more combinations that lead to that choice compared to buying a hot lunch or bringing lunch from home.