A car of mass 907 kg coasts on a level road, starting with an initial speed of 14.2 m/s and coming to rest 15.2 s later. Find the frictional force acting on the car.
force*time=mass*change velocity
mu*Mg*time= m*14.2
solve for mu.
To find the frictional force acting on the car, we can use the equation of motion that relates the distance covered by the car, its initial velocity, the time taken, and the acceleration.
First, let's find the acceleration of the car using the equation:
a = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 14.2 m/s
Final velocity (v) = 0 m/s
Time taken (t) = 15.2 s
Substituting these values into the equation, we can calculate the acceleration:
a = (0 - 14.2) / 15.2
Next, we'll calculate the acceleration (a):
a = -14.2 / 15.2
Now that we have the acceleration, we can determine the frictional force acting on the car. In this case, the frictional force opposes the motion of the car, so it has a direction opposite to the car's motion.
Using Newton's second law, F = m * a, where F is the frictional force, m is the mass of the car, and a is the acceleration:
F = 907 kg * (-14.2 / 15.2)
Calculating this expression will give us the magnitude of the frictional force acting on the car. However, since the frictional force opposes the motion of the car, it will be negative. Thus, the frictional force acting on the car is:
F = -847.2368 N
Therefore, the frictional force acting on the car is approximately -847.24 N.