HOw many cubic meter of water will an air tight rectangle box with a mass of 8000 kg and dimensions of 10m long 5m wide 3m tall displace when dropped in water? will it float?

V = L*W*h = 10 * 5 8 3 ,

= 150 m^3 = 1.50*10^8 cm^3 = Vol. of box.

Db = 8*10^6g * (1/1.5*10^8cm^3) = 0.0533 g/cm^3 . = Density ofbox.

Dw = 1g/cm^3 = Density of water.

Vb = (Db/Dw)*V,
Vb = (0.0533 / 1)*150 = 8 m^3 = Vol.
below water = Vol. of water displaced.

The box will float, because its' density is less than density of water.

Correction: V = 10 * 5 * 3 = 150 m^3.

To calculate the volume of water displaced by the rectangle box, we need to know its density and compare it to the density of water.

1. Finding the volume of the box:
The volume of a rectangular box can be calculated using the formula:
Volume = Length x Width x Height
Plugging in the given dimensions:
Volume = 10m x 5m x 3m = 150 cubic meters

2. Determining the density of water:
The density of water is approximately 1000 kg/m³.

3. Comparing the densities:
If the density of the box is greater than that of water, it will sink. If it is less, it will float. To find the density of the box, we can use the following formula:
Density = Mass / Volume

Density = 8000 kg / 150 m³ = 53.33 kg/m³

4. Analyzing the density comparison:
Since the density of the box (53.33 kg/m³) is less than the density of water (1000 kg/m³), the box will float when dropped into water.

As for the amount of water displaced, it will be equal to the volume of the box (150 cubic meters) when it floats.