A solution of H2SO4(aq) with a molal concentration of 1.94m has a density of 1.119g/mL. What is the molar concentration of this solution?

I got an answer of 2.17 M and it is incorrect..please help.

My work:
So Molar concentration = molal concentration * density
= 1.94 mol/kg * 1.119 kg/L = 2.17 M

Your error is that molar concn x density is NOT molality.

m = moles/kg solvet = 1.94 mol/kg solvent
How much is 1.94 moles H2SO4? That is M x L = 1.94 x 98 = about 190g (remember that's 1.94 mols).
It was dissolve in 1 kg solvent which is 1000 g. It had 190 g (approximate) H2SO4 for a total mass of 1000 +190 = 1190.
mass = volume x density or
volume = 1190 g/1.119 = about 1060 mL or 1.060 L.
So M = moles/L = 1.94 mol/1.063 L = about 1.8 M. You clean up the figures but 1.8 is close to the right answer.

Thanks so much! :] I understand my mistake!

Well, it looks like you've done all the right calculations, but unfortunately, you didn't get the correct answer. Don't worry, chemistry can be quite tricky sometimes.

Let's try to figure out where the mistake might be. When converting the density from grams per milliliter to kilograms per liter, did you remember to divide by 1000? Remember, there are 1000 milliliters in a liter. It's easy to overlook such tiny details sometimes.

Give it another shot, and remember, while chemistry can be serious business, it's also important to laugh at our mistakes. So keep the clown motto in mind: "If at first you don't succeed, try, try again, and then call in the clowns for a good laugh!"

To find the molar concentration of the solution, you need to convert the density from grams per milliliter (g/mL) to kilograms per liter (kg/L).

Given:
Molal concentration (m) = 1.94 m
Density = 1.119 g/mL

To convert the density to kg/L, you need to multiply by the conversion factor of 1000 g/kg and 1 L/1000 mL:

Density (kg/L) = 1.119 g/mL * (1 kg/1000 g) * (1000 mL/1 L)
Density (kg/L) = 1.119 kg/L

Now, you can calculate the molar concentration by multiplying the molal concentration by the density:

Molar concentration (M) = Molal concentration (m) * Density (kg/L)
Molar concentration (M) = 1.94 mol/kg * 1.119 kg/L
Molar concentration (M) = 2.17386 M (rounded to five decimal places)

Therefore, the molar concentration of the solution is approximately 2.17386 M.

To find the molar concentration of the solution, you need to convert the given density from grams per milliliter (g/mL) to kilograms per liter (kg/L). Then, you can use the formula you provided to calculate the molar concentration correctly.

Density is defined as mass divided by volume. In this case, the volume is given in milliliters, so you need to convert it to liters by dividing by 1000:

Density = 1.119 g/mL = 1.119 g / 1000 mL = 1.119 g / 1 L

Next, you need to convert the mass of the solution to kilograms. Since the molal concentration is given as mol/kg, it is necessary to express the mass in kilograms. To do this, divide the mass in grams by 1000:

Mass = 1.119 g = 1.119 g / 1000 g/kg = 0.001119 kg

Now you can substitute the values into the formula:

Molar concentration = molal concentration * density
Molar concentration = 1.94 mol/kg * 1.119 kg/L
Molar concentration = 2.17086 M

Therefore, the correct molar concentration of the solution is 2.17086 M, which can be rounded to 2.17 M. It seems that your calculation is indeed correct. It is important to use all the significant figures given in the question to avoid rounding errors. If your answer is still marked as incorrect, there might be a different issue, such as entering the answer incorrectly or misinterpreting the question.