I just need to know the net ionic equation and balance them. I figured the equation. but the net and balance is harder.
Co(NO3)2 (aq) + NaOH (aq) = CoOH (s) + Na(NO3)2 (aq)
Co(NO3)2 (aq) + Na2CO3 (aq) = CoCO3 (s) + Na2(NO3)2 (aq)
Co(NO3)2 (aq) + Na3PO4 (aq) = CoPO4 (s) + Na3(NO3)2 (aq)
Cu(NO3)2 (aq) + NaOH (aq) = CuOH (s) + Na(NO3)2 (aq)
Cu(NO3)2 (aq) + NaI (aq) = CuI (s) + Na(NO3)2 (aq)
Cu(NO3)2 (aq) + Na3PO4 (aq) = CuPO4 (s) + Na3(NO3)2 (aq)
Fe(NO3)3 (aq) + NaOH (aq) = FeOH (s) + Na(NO3)3 (aq)
Fe(NO3)3 (aq) + Na2CO3 (aq) = FeCO3 (s) + Na2(NO3)3 (aq)
Fe(NO3)3 (aq) + NaI (aq) =FeI (s) + Na(NO3)3 (aq)
Ba(NO3)3 (aq) + Na3PO4(aq) = BaPO4 (s) + Na3(NO3)3 (aq)
See your other posts Changing screen names doesn't help; actually it makes it more difficult to get answers.
To write the net ionic equation and balance the given chemical reactions, we need to follow a few steps:
Step 1: Write the balanced chemical equation for the reaction.
Co(NO3)2 (aq) + 2 NaOH (aq) → Co(OH)2 (s) + 2 NaNO3 (aq)
Co(NO3)2 (aq) + Na2CO3 (aq) → CoCO3 (s) + 2 NaNO3 (aq)
Co(NO3)2 (aq) + 3 Na3PO4 (aq) → CoPO4 (s) + 6 NaNO3 (aq)
Cu(NO3)2 (aq) + 2 NaOH (aq) → Cu(OH)2 (s) + 2 NaNO3 (aq)
Cu(NO3)2 (aq) + 2 NaI (aq) → CuI2 (s) + 2 NaNO3 (aq)
Cu(NO3)2 (aq) + 3 Na3PO4 (aq) → Cu3(PO4)2 (s) + 6 NaNO3 (aq)
Fe(NO3)3 (aq) + 3 NaOH (aq) → Fe(OH)3 (s) + 3 NaNO3 (aq)
Fe(NO3)3 (aq) + 3 Na2CO3 (aq) → Fe2(CO3)3 (s) + 6 NaNO3 (aq)
Fe(NO3)3 (aq) + 3 NaI (aq) → FeI3 (s) + 3 NaNO3 (aq)
Ba(NO3)2 (aq) + 3 Na3PO4 (aq) → Ba3(PO4)2 (s) + 6 NaNO3 (aq)
Step 2: Identify and separate the spectator ions from the remaining ions in the equation. Spectator ions are ions that do not participate in the reaction and remain unchanged on both sides.
In each reaction, the spectator ions are Na+ and NO3-.
Step 3: Write the net ionic equation by removing the spectator ions from the equation.
Co2+ (aq) + 2 OH- (aq) → Co(OH)2 (s)
Co2+ (aq) + CO32- (aq) → CoCO3 (s)
Co2+ (aq) + 3 PO43- (aq) → CoPO4 (s)
Cu2+ (aq) + 2 OH- (aq) → Cu(OH)2 (s)
Cu2+ (aq) + 2 I- (aq) → CuI2 (s)
Cu2+ (aq) + 3 PO43- (aq) → Cu3(PO4)2 (s)
Fe3+ (aq) + 3 OH- (aq) → Fe(OH)3 (s)
Fe3+ (aq) + 3 CO32- (aq) → Fe2(CO3)3 (s)
Fe3+ (aq) + 3 I- (aq) → FeI3 (s)
Ba2+ (aq) + 3 PO43- (aq) → Ba3(PO4)2 (s)
Step 4: Finally, make sure the net ionic equations are balanced by checking the number of atoms on each side of the equation.
It appears that you have already balanced the equations provided, so they are already balanced.
Note: The coefficients in the equations may vary depending on the specific conditions and stoichiometry of the reaction.