In the following reaction, how many grams of chlorine can be produced if 120 grams of titanium chloride (TiCl4) reacts with oxygen:
TiCl4(g) + O2(g) TiO2(s) + Cl2(g)
This is a stoichiometry problem. Here is a worked stoichiometry problem. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the number of grams of chlorine produced, we need to use the balanced chemical equation and perform stoichiometric calculations.
Step 1: Write the balanced chemical equation:
TiCl4(g) + O2(g) → TiO2(s) + Cl2(g)
Step 2: Determine the molar mass of TiCl4 and Cl2:
TiCl4: Titanium (Ti) has a molar mass of 47.867 g/mol, and chlorine (Cl) has a molar mass of 35.453 g/mol. Since there are four chlorine atoms in TiCl4, the molar mass of TiCl4 is (47.867 + 4 * 35.453) g/mol = 189.679 g/mol.
Cl2: Chlorine (Cl) has a molar mass of 35.453 g/mol.
Step 3: Calculate the moles of TiCl4:
Moles = mass / molar mass
Moles of TiCl4 = 120 g / 189.679 g/mol = 0.632 moles
Step 4: Use the stoichiometry to determine the moles of Cl2 produced:
According to the balanced equation, the mole ratio between TiCl4 and Cl2 is 1:1. Therefore, the moles of Cl2 produced will also be 0.632 moles.
Step 5: Convert moles of Cl2 to grams:
Mass = moles x molar mass
Mass of Cl2 = 0.632 moles x 35.453 g/mol = 22.403 g
Therefore, 22.403 grams of chlorine can be produced when 120 grams of titanium chloride (TiCl4) reacts with oxygen.