On a cold winter day in February, many students in Ms. Bush's sixth-grade class had runny noses and sore throats. After examining each student, the school nurse constructed the following table.

Sore Throat No Sore Throat
Runny Nose 7 14
No Runny Nose 6 6

Find the probability that a randomly selected student has a runny nose or a sore throa

a student earns 3 doller per hour baby sitting if she earned a total of 28.50 how many hours did she baby sit

you just divide 28.50 by 3 and the sum is the answer i am in fifth grade dude

On a cold winter day in February, many students in Ms. Bush's sixth-grade class had runny noses and sore throats. After examining each student, the school nurse constructed the following table.





Sore Throat

No Sore Throat

Runny Nose

9

2

No Runny Nose

11

6

0.88

To find the probability that a randomly selected student has a runny nose or a sore throat, we need to calculate the probability of two events: 1) having a runny nose, and 2) having a sore throat.

Given the information provided in the table, we can see that there are 7 students with both a runny nose and a sore throat. Additionally, there are 14 students with only a runny nose, and 6 students with only a sore throat.

To calculate the probability of having a runny nose or a sore throat, we add the probabilities of the two events:

Probability(runny nose or sore throat) = Probability(runny nose) + Probability(sore throat) - Probability(runny nose and sore throat)

Probability(runny nose) = (14 students with runny nose)/(total number of students)
Probability(sore throat) = (6 students with sore throat)/(total number of students)
Probability(runny nose and sore throat) = (7 students with runny nose and sore throat)/(total number of students)

Let's assume that there are a total of N students in Ms. Bush's sixth-grade class.

Probability(runny nose) = 14/N
Probability(sore throat) = 6/N
Probability(runny nose and sore throat) = 7/N

Now we can calculate the probability of having a runny nose or a sore throat:

Probability(runny nose or sore throat) = (14/N) + (6/N) - (7/N)

Simplifying the expression, we get:

Probability(runny nose or sore throat) = (14 + 6 - 7)/N

Therefore, the probability that a randomly selected student has a runny nose or a sore throat is (14 + 6 - 7)/N.

Note: Please replace N with the actual total number of students in Ms. Bush's sixth-grade class to get the specific probability.