an experiment was conducted by measuring the change in temperature of solutions after mixing them together.
After figuring out the KJ/mol, write a net ionic equation for each mixture
1) hydrochloric acid and sodium hydroxide (net ionic equation?)
2) nitric acid and sodium hydroxide
3)acetic acid and sodium hydroxide
I am not sure what to do for these, I know what net ionic equations are, but i was also told not to write down net ionic equations when there is no reaction (solid) being formed. and there are no solids (or precipitates being formed) so I would assume to not write a net ionic equation for either of them.
To determine whether a net ionic equation exists for these mixtures, you need to first identify if a reaction occurs between the reactants. In order for a reaction to occur, there must be a formation of a precipitate, gas, or water.
Let's consider each mixture separately:
1) Hydrochloric acid (HCl) and sodium hydroxide (NaOH):
When hydrochloric acid and sodium hydroxide react, they undergo a neutralization reaction to form water and a salt, sodium chloride (NaCl). The balanced equation for this reaction is:
HCl + NaOH -> H2O + NaCl
The net ionic equation for this reaction can be derived by canceling out the spectator ions, which are the ions that remain unchanged in the reaction. In this case, the net ionic equation would be:
H+ (aq) + OH- (aq) -> H2O (l)
2) Nitric acid (HNO3) and sodium hydroxide (NaOH):
Similar to the previous example, when nitric acid and sodium hydroxide react, a neutralization reaction occurs. The balanced equation for this reaction is:
HNO3 + NaOH -> H2O + NaNO3
Again, the net ionic equation can be determined by canceling out the spectator ions. In this case, the net ionic equation would be:
H+ (aq) + OH- (aq) -> H2O (l)
3) Acetic acid (CH3COOH) and sodium hydroxide (NaOH):
Acetic acid is a weak acid, and when it reacts with sodium hydroxide, it also undergoes a neutralization reaction. The balanced equation for this reaction is:
CH3COOH + NaOH -> H2O + CH3COONa
No precipitate or gas is formed in this reaction, so there is no net ionic equation.
Therefore, for mixtures 1 and 2, there are net ionic equations, but for mixture 3, there is no net ionic equation.