calculate molarity of NaOHin the solution prepared by dissolving its 4g in enough water to form 250ml of this solution ?
mols NaOH = grams/molar mass
The M = moles NaOH/L soln.
molarity=moles of solute/volume of whole solution in litres
so the mass of Na/molar mass of NaOH all divided by .250Litres
4g/40g divided by .250 litres is .4 M.
The answer is .4
To calculate the molarity of a solution, you need to know the number of moles of solute and the volume of the solution in liters.
First, we need to find the number of moles of NaOH. The formula weight (molar mass) of NaOH is 22.99 + 16.00 + 1.01 = 40.00 g/mol.
The number of moles of NaOH can be calculated using the formula:
moles = mass / molar mass
So, the number of moles of NaOH = 4 g / 40.00 g/mol = 0.1 mol
Now, we need to convert the volume of the solution from milliliters to liters.
The volume of the solution is 250 ml, which is equivalent to 250/1000 = 0.25 liters.
Now, we can calculate the molarity using the formula:
Molarity (M) = moles / volume (in liters)
Molarity of NaOH = 0.1 mol / 0.25 L = 0.4 M
Therefore, the molarity of the NaOH solution prepared by dissolving 4 g of NaOH in enough water to form a 250 ml solution is 0.4 M.