y=1/4x-1

1/2y=x-2
2x+3y=3
3y=5-2x
4x-y=3
4x=y=1
I don't understand this can someone please help me!
This is Systems of Equations
please work out the problem and explain it how to do it.

to make sure that they are separted

1.y=1/4x-1
1/2y=x-2
2.2x+3y=3
3y=5-2x
3.4x-y=3
4x-y=1

1. y=1/4x-1

1/2y=x-2
2. 2x+3y=3
3y=5-2x
3. 4x-y=3
4x-y=1

Did you post the first of these before?

If so, check this .....
http://www.jiskha.com/display.cgi?id=1329442868

no

To solve this system of equations, we will use the method of substitution. Here are the steps:

Step 1: Given equations:
y = 1/4x - 1 (Equation 1)
1/2y = x - 2 (Equation 2)
2x + 3y = 3 (Equation 3)
3y = 5 - 2x (Equation 4)
4x - y = 3 (Equation 5)
4x = y + 1 (Equation 6)

Step 2: Start by solving Equation 1 for y:
y = 1/4x - 1

Step 3: Substitute the value of y from Equation 1 into Equation 2:
1/2(1/4x - 1) = x - 2
Simplify:
1/8x - 1/2 = x - 2
Multiply both sides by 8 to eliminate fractions:
x - 4 = 8x - 16
Rearrange the equation:
7x = 12
Divide both sides by 7:
x = 12/7

Step 4: Substitute the value of x into Equation 1 to find y:
y = 1/4(12/7) - 1
Simplify:
y = 3/7 - 1
y = -4/7

Step 5: Check the solution by substituting the values of x and y into Equation 3:
2(12/7) + 3(-4/7) = 3
24/7 - 12/7 = 3
12/7 = 3
Both sides are equal, so the solution (x = 12/7, y = -4/7) is correct.

In conclusion, the solution to this system of equations is x = 12/7 and y = -4/7. If you have any further questions, feel free to ask!