The equation V=1/3 Bh gives the volume V of a pyramid, where B is the area of the base and h is the height. Solve this equation for B.
Please help me and show your work thanks
V = 1/3Bh
3(V)=Bh (multiply both side by 3 to cancel fraction)
3V/h=Bh/h (divide both by h to get rid of h)
3V/h=B
B=3V/h
i hate math :)
1. 3(v/b) or 3 x v/b
2. 12
To solve the equation V = (1/3) Bh for B, we need to isolate B on one side of the equation.
To do this, we can start by multiplying both sides of the equation by 3 to remove the fraction:
3 * V = 3 * (1/3) Bh
Simplifying the right side gives:
3V = Bh
Now, to isolate B, we can divide both sides of the equation by h:
(3V)/h = (Bh)/h
On the right side, the h cancels out, leaving us with:
(3V)/h = B
Therefore, the equation solved for B is:
B = (3V)/h
Now you have the formula to calculate the area of the base of a pyramid (B) given its volume (V) and height (h).