I have no idea how tp simplify 2 sq.root20-3 sq.root7-2 sq.root5+4 sq.root63? I guessed 2 sq.root5-3 sq.root7+4 sq.root63 is it right?
I'm going to assume your problem is this:
2√20 - 3√7 - 2√5 + 4√63
√20 breaks down to √5*2*2
√63 breaks down to √7*3*3
Therefore:
2√20 becomes 4√5
4√63 becomes 12√7
Now we have:
4√5 - 3√7 - 2√5 + 12√7
Combine like terms and simplify:
2√5 + 9√7
That is as far as you can go.
I hope this helps and is what you were asking.
Solution for 9th std all sums
To simplify the expression 2√20 - 3√7 - 2√5 + 4√63, you need to simplify the square roots and then combine like terms.
Let's start by simplifying each square root:
√20 can be broken down as √(4 * 5). Since √4 is 2, we get 2√5.
√63 can be simplified as √(9 * 7). Since √9 is 3, we get 3√7.
Now, let's rewrite the expression with the simplified square roots:
2√5 - 3√7 - 2√5 + 4(3√7).
Notice that we have like terms: 2√5 and -2√5 can be combined, and -3√7 and 4(3√7) can also be combined. This simplifies the expression to:
0 - √7 + 12√7.
Finally, combining the like terms, we have:
12√7 - √7.
This can be further simplified as:
11√7.
So, the simplified expression is 11√7.