This isn't so much a question, but a query:

What does this mean?
K.E. = 1/2 mv2
I can do the homework on my own if someone lets me know. Thanks.

Ke = (1/2) m v^2

is the kinetic energy of a mass m moving at speed v

now as a simple example think of a mass m at rest. We push on it with a force F and it accelerates with a = F/m

The speed is
v = a t
The distance is
d = (1/2) a t^2
The work in is
F * d = m a d
If all is well and no energy is lost then the work in = the kinetic energy
but work in as we said is
m a d = m (1/2) a^2 t^2
but we know that v^2 = a^2 t^2
so
work in = (1/2)m v^2
so
Ke = (1/2) m v^2

The equation you mentioned is the formula for calculating the kinetic energy (K.E.) of an object. Let me break it down for you.

K.E. stands for kinetic energy, which is the energy possessed by an object due to its motion. The equation is derived from the laws of physics and can be used to calculate the kinetic energy of an object if you know its mass (m) and velocity (v).

To understand the equation, it is helpful to know that "1/2" is a fraction equivalent to 0.5. So, the equation can also be written as:

K.E. = 0.5 * m * v^2

Here's how you can use the formula:
1. Determine the mass (m) of the object in question. The mass is a measure of how much matter an object contains.
2. Determine the velocity (v) of the object. This refers to the speed at which it is moving.
3. Square the value of the velocity (v^2) by multiplying it by itself.
4. Multiply the squared velocity (v^2) by the mass (m).
5. Finally, multiply the result by 0.5 (or divide it by 2) to find the value of the kinetic energy (K.E.).

For example, let's say you have a car with a mass of 1000 kilograms (m) and it is traveling at a velocity of 20 meters per second (v). Plug these values into the equation:

K.E. = 0.5 * 1000 kg * (20 m/s)^2

To calculate the result:
1. Square the velocity: (20 m/s)^2 = 400 m^2/s^2
2. Multiply the squared velocity by the mass: 0.5 * 1000 kg * 400 m^2/s^2 = 200,000 Joules (J)

So, the kinetic energy of the car would be 200,000 Joules.

I hope this explanation helps you understand the equation better and enables you to do your homework. If you have any further questions, feel free to ask!