physics

A particle that undergoes simple harmonic motion has a period of 0.4 s and an amplitude of 12 mm. The maximam velocity of the particle is?

  1. 0
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asked by Abdela
  1. y = .012 sin (2pi t/.4)

    v = dy/dt = (.012)(2 pi/.4)cos (2 pi t/.4)

    max v = .012 * 2 * pi / .4

    1. 0
    posted by Damon

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