Math

Find a linear equation whose graph is the straight line with the given property.
Through (2, −7) and (1, 1)

I got -8x-23, I know it doesn't match, maybe its the wrong formula

Find a linear equation whose graph is the straight line with the given property.
Through
(1/4, −1)and parallel to the line
4x − 5y = 5

How do I make it parallel?

Thank you.

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  1. slope = (1+7)/(1-2) = -8

    I don't know what method or "formula" you have been taught, but using the slope-yintercept form seems to be a popular method these days.

    y = mx + b
    y = -8x + b
    sub in the point (1,1) , (I always use the "easier" point)
    1 = -8 + b
    b = 9

    equation : y = -8x + 9
    or
    8x + y = 9

    The second one is even easier.
    Since the new line is parallel to the given line, it must look like
    4x - 5y = c , differing only in the constant term
    sub in the given point (1/4 , -1)
    4(1/4) - 5(-1) = c
    c = 1 + 5 = 6

    new equation: 4x - 5y = 6

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