What is the potential halfway between two point charges spaced 1 mm apart if q1=10 micro culumbs and q2= -5 micro culumbs
distance=.0005mm
V=k (sum charge/distance)
But v= k int. (Dq/r).....?
To find the potential at the halfway point between two point charges, we can use the concept of electric potential.
The electric potential at a point due to a point charge can be calculated using the equation:
V = k * (q / r)
Where:
V is the electric potential,
k is the electrostatic constant (approximately 9 x 10^9 Nm^2/C^2),
q is the charge, and
r is the distance from the charge.
Let's consider two point charges, q1 and q2, spaced 1 mm apart. We have q1 = 10 μC (microcoulombs) and q2 = -5 μC.
To get the potential midway between the two charges, we need to find the electric potentials at their respective positions and then calculate the average potential.
First, let's calculate the electric potential at the position of q1:
V1 = k * (q1 / r)
Here, r is the distance from q1 to the halfway point. Since the charges are spaced 1 mm apart, the distance from q1 to the halfway point is half of 1 mm, which is 0.5 mm or 0.0005 m.
Substituting the values into the equation:
V1 = (9 x 10^9 Nm^2/C^2) * (10^-5 C) / (0.0005 m)
Next, let's calculate the electric potential at the position of q2:
V2 = k * (q2 / r)
Here, r is also 0.0005 m, as the halfway point is equidistant from q1 and q2.
Substituting the values:
V2 = (9 x 10^9 Nm^2/C^2) * (-5 x 10^-6 C) / (0.0005 m)
Now, we can find the average potential by taking the arithmetic mean of V1 and V2:
V_avg = (V1 + V2) / 2
Calculate the values of V1, V2, and V_avg using the provided formulas, and you will find the potential at the halfway point between the two charges.