a 100 mL {100 grams} of water at 4.0 degrees celsius is heated until its tempurture is 37 degrees celcus. if the specific heat of water is 4.18 joules/grams degrees celcus calculate the amount of heat energy needed to cause this rise in tempurture
To calculate the amount of heat energy needed to cause the rise in temperature, we will use the formula:
Q = m * c * ΔT
Where:
Q is the heat energy (in joules)
m is the mass of the water (in grams)
c is the specific heat capacity of water (in joules/gram°C)
ΔT is the change in temperature (in °C)
In this case:
m = 100 grams
c = 4.18 joules/gram°C
ΔT = 37°C - 4°C = 33°C
Now, we can plug these values into the formula to calculate the heat energy:
Q = 100 grams * 4.18 joules/gram°C * 33°C
Q = 13827 joules
Therefore, the amount of heat energy needed to raise the temperature of 100 grams of water from 4.0°C to 37.0°C is 13,827 joules.
To calculate the amount of heat energy needed to cause the rise in temperature, you can use the formula:
Q = m * c * ΔT
where:
Q = heat energy (in joules)
m = mass of water (in grams)
c = specific heat of water (in joules/gram°C)
ΔT = change in temperature (in °C)
Given:
m = 100 grams
c = 4.18 joules/gram°C
ΔT = 37°C - 4.0°C
Substituting the values into the formula, we have:
Q = 100 grams * 4.18 joules/gram°C * (37°C - 4.0°C)
Q = 100 grams * 4.18 joules/gram°C * 33°C
Q = 138174 joules
Therefore, the amount of heat energy needed to cause the rise in temperature is 138174 joules.