What is the magnitude of an electrostatic force experienced by one elementary charge at a point in an electric field where the field intensity is 3.0 x 10^3 newtons per coulomb?
a) 1.0 x 10^3 N
b) 1.6 x 10^-19 N
c) 3.0 x 10^3 N
d) 4.8 x 10^-16 N
it is d
The magnitude of the electrostatic force experienced by one elementary charge can be calculated using the equation:
F = q * E
Where F is the electrostatic force, q is the charge, and E is the electric field intensity.
In this case, we are given the electric field intensity (E) as 3.0 x 10^3 N/C. The elementary charge (q) is typically represented as e and has a value of 1.6 x 10^-19 C.
Using the formula and substituting the values, we get:
F = (1.6 x 10^-19 C) * (3.0 x 10^3 N/C)
F = 4.8 x 10^-16 N
Therefore, the magnitude of the electrostatic force experienced by one elementary charge is 4.8 x 10^-16 N.
The correct option is D) 4.8 x 10^-16 N.
To find the magnitude of the electrostatic force experienced by one elementary charge at a point in an electric field, you can use the equation:
F = qE
where F is the force, q is the charge, and E is the electric field intensity. In this case, the charge q is the elementary charge, which is defined as 1.6 x 10^-19 coulombs.
So, to calculate the force:
F = (1.6 x 10^-19 C)(3.0 x 10^3 N/C)
F = 4.8 x 10^-16 N
Therefore, the magnitude of the electrostatic force experienced by one elementary charge at a point in an electric field is 4.8 x 10^-16 N.
The correct answer is option d) 4.8 x 10^-16 N.