The purity of a pharmaceutical preparation of sulfanilamide, C6H4N2O2S, can be determined by oxidizing the sulfur to SO2 and bubbling the SO2 through H2O2 to produce H2SO4. The acid is then titrated with standard NaOH. Calculate the purity (%w/w sulfanilamide) given that 1.457 g of the sulfanilamide sample required 20.6 mL of 0.3443 M NaOH. (Note: 1 mol sulfanilamide = 1mol S = 1mol H2SO4)

Question

The purity of a pharmaceutical preparation of sulfanilamide, C6H4N2O2S, can be determined by oxidizing the sulfur to SO2 and bubbling the SO2 through H2O2 to produce H2SO4. The acid is then titrated with standard NaOH. Calculate the purity (%w/w sulfanilamide) given that 1.457 g of the sulfanilamide sample required 20.6 mL of 0.3443 M NaOH. (Note: 1 mol sulfanilamide = 1mol S = 1mol H2SO4)

Answer 1

The titration step is

2NaOH + H2SO4 ==> 2H2O + Na2SO4.

moles NaOH = M x L = ?
Convert to moles H2SO4.
moles NaOH x (1 mol H2SO4/2 mol NaOH) = ?
moles H2SO4 = moles sulfanilamide according to your information.
g sulfanilamide = moles sulf x molar mass sulf
%purity = (mass sulf/mass sample)*100 = ?

Answer 2

Well, determining the purity of a pharmaceutical preparation sounds like a serious task. I'm here to lighten things up, but I'll try to help you with the calculation as well.

To calculate the purity (%w/w) of sulfanilamide, we need to find the number of moles of sulfanilamide and H2SO4, and then compare them to get the percentage.

First, let's calculate the number of moles of NaOH used in the titration. We can use the formula:

moles NaOH = concentration (M) * volume (L)

Plugging in the values, we have:

moles NaOH = 0.3443 M * 0.0206 L = 0.00709878 moles NaOH

Since 1 mol sulfanilamide is equal to 1 mol H2SO4, we have 0.00709878 moles of H2SO4. So, we also have 0.00709878 moles of sulfanilamide.

To calculate the mass of sulfanilamide, we'll use its molar mass:

molar mass of sulfanilamide = (6*12.01) + (4*1.008) + 2*(14.01) + 32.06 = 172.19 g/mol

Plugging in the values, we have:

mass sulfanilamide = 0.00709878 moles * 172.19 g/mol = 1.22039 g

Finally, we can calculate the purity (%w/w) using the formula:

purity (%w/w) = (mass sulfanilamide / mass sample) * 100

Plugging in the values, we have:

purity (%w/w) = (1.22039 g / 1.457 g) * 100 ≈ 83.88%

So, the purity of the sulfanilamide sample is approximately 83.88%. I hope that helps, and remember, a little humor can go a long way when dealing with serious calculations like this!

Answer 3

To calculate the purity of sulfanilamide (%w/w), we need to determine the number of moles of sulfanilamide and the number of moles of NaOH used in the titration.

Step 1: Determine the moles of NaOH used.
Moles of NaOH = Molarity of NaOH x Volume of NaOH
Moles of NaOH = 0.3443 M x 20.6 mL
Moles of NaOH = 0.3443 mol/L x 0.0206 L
Moles of NaOH = 0.00709678 mol

Step 2: Determine the number of moles of H2SO4 produced.
Since 1 mol of sulfanilamide reacts with 1 mol of sulfur and produces 1 mol of H2SO4, the number of moles of H2SO4 is equal to the number of moles of sulfanilamide.

Moles of H2SO4 = Moles of sulfanilamide = 0.00709678 mol

Step 3: Convert the moles of H2SO4 to grams of sulfanilamide.
Molar mass of H2SO4 = 98.09 g/mol (from periodic table)
Mass of sulfanilamide = Moles of H2SO4 x Molar mass of H2SO4
Mass of sulfanilamide = 0.00709678 mol x 98.09 g/mol
Mass of sulfanilamide = 0.695 g

Step 4: Calculate the purity of sulfanilamide.
Purity (%w/w) = (Mass of sulfanilamide / Mass of sample) x 100%
Purity (%w/w) = (0.695 g / 1.457 g) x 100%
Purity (%w/w) = 47.74%

Therefore, the purity of the sulfanilamide sample is approximately 47.74% w/w.

Answer 4

To calculate the purity (%w/w sulfanilamide) of the sample, we need to determine the number of moles of sulfanilamide present in the sample and then calculate the percentage.

Let's break down the steps:

Step 1: Determine the number of moles of NaOH used in the titration.
Using the given information, we know that the volume of NaOH used is 20.6 mL and the molarity of NaOH is 0.3443 M.
Number of moles of NaOH = volume (in liters) x molarity
= 20.6 mL / 1000 mL/L x 0.3443 mol/L
= 0.007078 mol

Step 2: Determine the number of moles of H2SO4 formed.
Since the reaction between NaOH and H2SO4 is 1:1, the moles of NaOH used is the same as the moles of H2SO4 formed.

Step 3: Determine the number of moles of Sulfanilamide (C6H4N2O2S).
As given in the question, 1 mole of sulfanilamide is equivalent to 1 mole of sulfur (S) and 1 mole of H2SO4.
Therefore, the moles of sulfanilamide = moles of H2SO4

Step 4: Calculate the mass of sulfanilamide.
To determine the mass of sulfanilamide, we need to know the molar mass of sulfanilamide (C6H4N2O2S).

C (carbon) = 12.01 g/mol
H (hydrogen) = 1.01 g/mol
N (nitrogen) = 14.01 g/mol
O (oxygen) = 16.00 g/mol
S (sulfur) = 32.07 g/mol

Molar mass of sulfanilamide = (6 x C) + (4 x H) + (2 x N) + (2 x O) + S
= (6 x 12.01) + (4 x 1.01) + (2 x 14.01) + (2 x 16.00) + 32.07
= 172.19 g/mol

Mass of sulfanilamide = moles of sulfanilamide x molar mass
= 0.007078 mol x 172.19 g/mol

Step 5: Calculate the percentage purity of sulfanilamide.
Percentage purity (%w/w) = (Mass of pure sulfanilamide / Total mass of the sample) x 100

Now you can perform the calculations using the given values and the steps mentioned above to find the percentage purity of sulfanilamide.

The titration step is

58.5%

Well, determining the purity of a pharmaceutical preparation sounds like a serious task. I'm here to lighten things up, but I'll try to help you with the calculation as well.

To calculate the purity of sulfanilamide (%w/w), we need to determine the number of moles of sulfanilamide and the number of moles of NaOH used in the titration.

To calculate the purity (%w/w sulfanilamide) of the sample, we need to determine the number of moles of sulfanilamide present in the sample and then calculate the percentage.